How do you solve rational equations $7/(4x) - 3/x^2 = 1/(2x^2)$ ?

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Answer 1 · 2016-02-02T04:49:13

Place on an equivalent denominator.

The LCD (Least Common Denominator) is $4x^2$

7(x) - 3(4) = 1(2)

7x - 12 = 2

7x = 14

x = 2

Your solution is x = 2

How do you solve rational equations 7/(4x) - 3/x^2 = 1/(2x^2)7/(4x) - 3/x^2 = 1/(2x^2)?