How do you solve $\sqrt[3]{x} + 10 = 16$ $root3(x)+10=16$ ?

Question

How do you solve $\sqrt[3]{x} + 10 = 16$ $root3(x)+10=16$ ?

1 Answer

Impact of this question

1444 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-07-29T19:20:18

$x = 216$ $x=216$

Explanation:

$\sqrt[3]{x} + 10 = 16$ $root3x+10=16$
or
$\sqrt[3]{x} = 16 - 10$ $root3x=16-10$
or
$\sqrt[3]{x} = 6$ $root3x=6$
or
$x = 6$ $x=6$ x $6$ $6$ x $6$ $6$
or
$x = 216$ $x=216$

Science

Math

Humanities

... and beyond

How do you solve $\sqrt[3]{x} + 10 = 16$ $root3(x)+10=16$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you solve root3(x)+10=163√x+10=16root3(x)+10=16?

1 Answer

Explanation:

Related questions

Impact of this question

How do you solve $\sqrt[3]{x} + 10 = 16$ $root3(x)+10=16$ ?