How do you solve # s + 9/10 = 1/2#?

1 Answer
Feb 19, 2017

See the entire solution process below:

Explanation:

First, multiply each side of the equation by #color(red)(10)# to eliminate the fractions while keeping the equation balanced:

#color(red)(10)(s + 9/10) = color(red)(10) xx 1/2#

#(color(red)(10) xx s) + (color(red)(10) xx 9/10) = cancel(color(red)(10)) 5 xx 1/color(red)(cancel(color(black)(2)))#

#10s + (cancel(color(red)(10)) xx 9/color(red)(cancel(color(black)(10)))) = 5#

#10s + 9 = 5#

Next, subtract #color(red)(9)# from each side of the equation to isolate the #s# term while keeping the equation balanced:

#10s + 9 - color(red)(9) = 5 - color(red)(9)#

#10s + 0 = -4#

#10s = -4#

Now, divide each side of the equation by #color(red)(10)# to solve for #s# while keeping the equation balanced:

#(10s)/color(red)(10) = -4/color(red)(10)#

#(color(red)(cancel(color(black)(10)))s)/cancel(color(red)(10)) = -2/5#

#s = -2/5#