Question

How do you solve `sqrt(2x + 7) = 6`?

Answer 1

`x=29/2`

Explanation:

`color(blue)"square both sides"`

`rArr(sqrt(2x+7))^2=6^2`

`rArr2x+7=36`

`"subtract 7 from both sides"`

`rArr2x=29rArrx=29/2`

`color(blue)"As a check"`

Substitute this value into the left side of the equation and if equal to the right side then it is the solution.

`sqrt(29+7)=sqrt36=6=" right side"`

`rArrx=29/2" is the solution"`