How do you solve $\sqrt{- 32 - 12 x} = x$ $\sqrt { - 32- 12x } = x$ ?

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Answer 1 · 2018-06-09T09:13:44

No real solutions

After squaring we get

$0 = x^{2} + 12 x + 32$ $0=x^2+12x+32$
$x_{1, 2} = - 6 \pm 2$ $x_(1,2)=-6pm 2$
so we get

$x_{1} = - 4$ $x_1=-4$
$x_{2} = - 8$ $x_2=-8$
which are no Solutions since we have $x \geq 0 .$ $x>=0.$

How do you solve \sqrt { - 32- 12x } = x√−32−12x=x\sqrt { - 32- 12x } = x?