How do you solve $\sqrt{3 x - 2} - 5 = 0$ $sqrt(3x-2) - 5 =0$ ?

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Answer 1 · 2016-07-24T11:29:43

$x = 9$ $x=9$

$\sqrt{3 x - 2} = 5$ $sqrt(3x-2)=5$ . Squaring both sides, we get $3 x - 2 = 25 or 3 x = 27 or x = 9$ $3x-2=25 or 3x=27 or x=9$ [Ans]

How do you solve sqrt(3x-2) - 5 =0√3x−2−5=0sqrt(3x-2) - 5 =0?