How do you solve $sqrt(4n) =2$ and find any extraneous solutions?

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Answer 1 · 2017-04-15T15:55:39

$color(blue)(n=1$

$sqrt(4n)=2$

square each side

$:,(sqrt(4n))^2=(2)^2$

$:.sqrt(4n)*sqrt(4n)=4n$

$:.4n=4$

$:.color(blue)(n=1$

How do you solve sqrt(4n) =2sqrt(4n) =2 and find any extraneous solutions?