How do you solve $\sqrt{4 x - 3} = x$ $sqrt[4x-3]=x$ ?

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How do you solve $\sqrt{4 x - 3} = x$ $sqrt[4x-3]=x$ ?

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Answer 1 · 2015-04-18T02:18:01

Try squaring both sides to get:
$4 x - 3 = x^{2}$ $4x-3=x^2$
$x^{2} - 4 x + 3 = 0$ $x^2-4x+3=0$
Now solve the equation to find two values of $x$ $x$ .
At the end check them into your original equation.

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How do you solve $\sqrt{4 x - 3} = x$ $sqrt[4x-3]=x$ ?

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