How do you solve $\sqrt { 5x - 9} - 9= 0$ ?

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Answer 1 · 2016-10-15T08:38:44

$x = 18$

Making $5x-9 = 9^2$ we have

$9-9=0$ so

$x = (9^2+9)/5=90/5=18$

Answer 2 · 2016-10-15T08:39:03

x=18

$sqrt(5x-9)-9=0$
$sqrt(5x-9)=9$
Squaring both sides
$5x-9=81$
$5x=81+9=90$
$x=90/5=18$

How do you solve \sqrt { 5x - 9} - 9= 0\sqrt { 5x - 9} - 9= 0?