How do you solve $sqrt(7x-6)=x$ ?

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Answer 1 · 2015-04-09T23:57:03

$sqrt(7x-6) = x => 7x-6 = x^2 => 0= x^2-7x+6$
Therefore $0= (x-6)*(x-1)$

So there will be two result of x;
One of them is (x-6)=0 $=>$ x=6
And the other one is (x-1)=0 $=>$ x=1

How do you solve sqrt(7x-6)=xsqrt(7x-6)=x?