How do you solve $\sqrt{8 x + 1} = 5$ $sqrt(8 x + 1) = 5$ ?

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Answer 1 · 2015-08-06T06:19:35

$x = 3$ $color(blue)(x=3$

$\sqrt{8 x + 1} = 5$ $sqrt(8x+1) = 5$

Squaring both sides

${(\sqrt{8 x + 1})}^{2} = 5^{2}$ $(sqrt(8x+1))^2 = 5^2$

$8 x + 1 = 25$ $8x+1 =25$

$8 x = 25 - 1$ $8x = 25-1$

$8 x = 24$ $8x=24$

$x = 3$ $color(blue)(x=3$

How do you solve sqrt(8 x + 1) = 5√8x+1=5sqrt(8 x + 1) = 5?