How do you solve $sqrt(8 x + 1) = 5$ and find any extraneous solutions?

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Answer 1 · 2016-07-07T15:53:35

$x = 3$

Square both sides

$(sqrt(8x+1))^2 = 5^2$

$8x + 1 = 25$

Isolate the variable term

$8x = 24$

Isolate the variable (get rid of the coefficient)

$x = 3$

All values leading up to but not including $-1/8$ are when the equation is undefined.

How do you solve sqrt(8 x + 1) = 5sqrt(8 x + 1) = 5 and find any extraneous solutions?