How do you solve $sqrt(8x) + 3 = 7$ ?

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Answer 1 · 2015-09-21T07:45:04

$x=2$

Given-
$sqrt(8x)+3=7$

[Add $-3$ on both sides]

$sqrt(8x)+3-3=7-3$

$sqrt(8x)=4$

Square both sides

$8x=16$
$x=16/8=2$

How do you solve sqrt(8x) + 3 = 7 sqrt(8x) + 3 = 7?