How do you solve $sqrt(x -1) = x - 3$ ?

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Answer 1 · 2018-04-25T23:15:24

x=2,5

To remove the square root, square both sides

$x-1=(x-3)^2$

Square the right side

$(x-3)^2=(x-3)(x-3)=x^2-3x-3x+9$

$x-1=x^2-6x+9$

Combine terms and set equation to 0

$0=x^2-7x+10$

Factor

$0=(x-2)(x-5)$

How do you solve sqrt(x -1) = x - 3sqrt(x -1) = x - 3?