How do you solve $\sqrt{x - 5} = 2 \sqrt{6}$ $sqrt(x-5) = 2sqrt6$ ?

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How do you solve $\sqrt{x - 5} = 2 \sqrt{6}$ $sqrt(x-5) = 2sqrt6$ ?

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Answer 1 · 2016-05-25T21:59:42

$x = 29$ $x=29$

Explanation:

Square both sides.

${(\sqrt{x - 5})}^{2} = {(2 \sqrt{6})}^{2}$ $(sqrt(x-5))^2=(2sqrt6)^2$

On the left side, the square root and the exponent of $2$ $2$ undo one another, leaving just $x - 5$ $x-5$ .

On the right side, to square $2 \sqrt{6}$ $2sqrt6$ , we see that ${(2 \sqrt{6})}^{2} = 2^{2} \cdot {(\sqrt{6})}^{2} = 4 \cdot 6 = 24$ $(2sqrt6)^2=2^2*(sqrt6)^2=4*6=24$ .

$x - 5 = 24$ $x-5=24$

$x = 29$ $x=29$

Answer 2 · 2016-05-25T21:59:57

$x = 29$ $x = 29$

Explanation:

square both sides
$x - 5 = {(2 \sqrt{6})}^{2} \to x - 5 = 2^{2} \times 6 \to x - 5 = 24$ $x - 5 = (2sqrt6)^2 -> x - 5 = 2^2 xx 6 -> x - 5 = 24$
add 5 to both sides
$x = 29$ $x = 29$

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How do you solve $\sqrt{x - 5} = 2 \sqrt{6}$ $sqrt(x-5) = 2sqrt6$ ?

2 Answers

Explanation:

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How do you solve √x−5=2√6sqrt(x-5) = 2sqrt6?

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How do you solve $\sqrt{x - 5} = 2 \sqrt{6}$ $sqrt(x-5) = 2sqrt6$ ?