How do you solve $\sqrt{x - 5} + 7 = 3$ $sqrt(x-5) + 7 = 3$ ?

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Answer 1 · 2015-06-22T00:25:38

There is no real solution.

Subtracting $7$ $7$ on both sides, we get:
$\sqrt{x - 5} = - 4$ $sqrt(x-5)=-4$

And the result of a square root (by definition) can never be negative.

How do you solve √x−5+7=3sqrt(x-5) + 7 = 3?