How do you solve $\sqrt{- x} + 52 = 8$ $sqrt(-x) + 52 = 8$ ?

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How do you solve $\sqrt{- x} + 52 = 8$ $sqrt(-x) + 52 = 8$ ?

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Answer 1 · 2015-04-15T22:04:51

I would take the $52$ $52$ to the right:
$\sqrt{- x} = 8 - 52$ $sqrt(-x)=8-52$
Square both sides:
${(\sqrt{- x})}^{2} = {(- 44)}^{2}$ $(sqrt(-x))^2=(-44)^2$
$- x = 1936$ $-x=1936$
$x = - 1936$ $x=-1936$
BUT this solution, plugged back into your original equation, DOES NOT WORK.
I think your equation doesn't have REAL solutions.

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How do you solve $\sqrt{- x} + 52 = 8$ $sqrt(-x) + 52 = 8$ ?

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How do you solve √−x+52=8sqrt(-x) + 52 = 8?

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How do you solve $\sqrt{- x} + 52 = 8$ $sqrt(-x) + 52 = 8$ ?