How do you solve $sqrt(x+6) = 3 + sqrtx$ ?

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Answer 1 · 2015-09-28T16:24:20

See the explanation.

If $sqrt(x+6) = 3 + sqrtx$ , then

$(sqrt(x+6))^2 = (3 + sqrtx)^2$ (but not necessarily vie-versa)

So, $x+6 = 9 + 6sqrtx+x$

Which would require
$-3 = 6sqrtx$

But this is not possible, because $sqrtx$ is never negative.

So, the equation has no solutions..

How do you solve sqrt(x+6) = 3 + sqrtxsqrt(x+6) = 3 + sqrtx?