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How do you solve $sqrt(x-6)=sqrt(1/3x)=0$ ?

1 Answer

Sep 4, 2016

No value of $x$ satisfies both equalities.

Explanation:

$sqrt(x-6)=sqrt(1/3x)$
$color(white)("XXX")rarrx-6=1/3x$

$color(white)("XXX")rarr3x-18=x$

$color(white)("XXX")rarr2x=18$
$color(white)("XXX")rarrx=9$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$sqrt(1/3x)=0$
$color(white)("XXX")rarrx=0$

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

$sqrt(x-6)=0$
$color(white)("XXX")rarrx-6=0$

$color(white)("XXX")rarrx=6$

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