How do you solve sqrtj + sqrtj + 14 = 3sqrtj +10 √j+√j+14=3√j+10?

2 Answers
Tony B
Feb 28, 2016

j=16j=16

Explanation:

Given:" "sqrt(j) + sqrt(j)+14" "=" "3sqrt(j)+10 √j+√j+14 = 3√j+10

Write as:" " 2sqrt(j)+14" "=" "3sqrt(j)+10 2√j+14 = 3√j+10

Collecting like terms

" "3sqrt(j)-2sqrt(j)" " =" "14-10 3√j−2√j = 14−10

sqrt(j)" "=" "4√j = 4

Squaring both sides

j=4^2=16j=42=16

Jim G.
Feb 28, 2016

j = 16

Explanation:

Collect terms in j to the left and numbers to the right.

hence 2sqrtj - 3sqrtj = 10 - 14 → -sqrtj = -42√j−3√j=10−14→−√j=−4

multiply both sides by (-1) to obtain : sqrtj = 4 √j=4

now square both sides.

rArr (sqrtj)^2 = 4^2 rArr j = 16 ⇒(√j)2=42⇒j=16

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