How do you solve $\sqrt{x} = \frac{1}{9}$ $sqrtx=1/9$ ?

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Answer 1 · 2016-08-19T06:51:40

$x = \frac{1}{81}$ $x=1/81$ .

$\sqrt{x} = \frac{1}{9}$ $sqrtx=1/9$

$\Rightarrow {(\sqrt{x})}^{2} = {(\frac{1}{9})}^{2}$ $rArr (sqrtx)^2=(1/9)^2$

$\Rightarrow x = \frac{1}{81}$ $rArr x=1/81$ .

This root satisfies the given eq,.

How do you solve √x=19sqrtx=1/9?