How do you solve $sqrtx+3sqrtx=sqrt(17x-4)$ ?

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Answer 1 · 2017-05-28T11:07:18

$x= 4$

$sqrt(x) + 3sqrt(x) = sqrt (17x-4) or sqrt x (3+1) = sqrt (17x-4)$ or

$4sqrt(x) = sqrt (17x-4)$ , squaring both sides we get,

$16 x = 17x -4 or x = 4$ [Ans]

How do you solve sqrtx+3sqrtx=sqrt(17x-4)sqrtx+3sqrtx=sqrt(17x-4)?