How do you solve the equation $2 + (3/(x-1)) = 10$ ?

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Answer 1 · 2018-04-02T14:45:19

$x=11/8$

$2+(3/(x-1))$ =10
$(3/(x-1))$ =8
$3=8(x-1)$
$3=8x-8$
$11=8x$
$x=11/8$

Answer 2 · 2018-04-02T14:50:48

$x=1 3/8$

$2+3/(x-1)=10$
$rArr (2(x-1)+3)/(x-1)=10$
$rArr2x-2+3=10(x-1)$
$rArr2x+1=10x-10$
$rArr8x=11$
$x=11/8$
$:.x=1 3/8$

How do you solve the equation 2 + (3/(x-1)) = 102 + (3/(x-1)) = 10?