Question

How do you solve the equation `3x+16=31`?

Answer 1

`x=5`

Explanation:

Given -

`3x+16=31`

Add `-16` to both sides

`3x+16 -16=31-16`

`3xcancel(+16) cancel( -16)=15`

`3x=15`

Divide both sides by `3`

`(3x)/3=15/3`

`(cancel3x)/cancel3=5`

`x=5`