How do you solve the rational equation $2/ (5x-1) - 2/(3x+5) = 0$ ?

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Answer 1 · 2016-02-20T04:06:12

Put on an equal denominator

The Least Common Denominator would be $(5x - 1)(3x + 5)$

$(2(3x + 5))/((5x - 1)(3x + 5)) - (2(5x - 1))/((3x + 5)(5x - 1)) = 0$

Eliminating the denominators

6x + 10 - (10x - 2) = 0

-4x = -8

x = 2

Hopefully this helps!

How do you solve the rational equation 2/ (5x-1) - 2/(3x+5) = 02/ (5x-1) - 2/(3x+5) = 0?