How do you solve the rational equation $(x+2)/(x+1)-(x-4)/(x-3)=0$ ?

Question

1499 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-08T06:50:39

$x=1$

add $[x-4]/[x-3]$ to both sides

$[x+2]/[x+1]=[x-4]/[x-3]$

multiply both sides by $(x+1)(x-3)$

$(x-3)(x+2)=(x-4)(x+1)$

$x^2+2x-3x-6=x^2+x-4x-4$

$x^2-x-6=x^2-3x-4$

add $x^2$ to both sides

$-x-6=-3x-4$

add $3x$ to both sides

$2x-6=-4$

add 6 to both sides

$2x=2$

divide by 2

$x=1$

How do you solve the rational equation (x+2)/(x+1)-(x-4)/(x-3)=0(x+2)/(x+1)-(x-4)/(x-3)=0?