How do you solve the rational equation $(y+2)/y = 1/(y-5)$ ?

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Answer 1 · 2018-05-20T00:23:42

$y=2+-sqrt14$

$(y+2)/y = 1/(y-5)$

$(y+2)(y-5) = y$

$y^2-3y-10=y$

$y^2-4y-10=0$

$y=(-b+-sqrt(b^2-4ac))/(2a)$

$y=(4+-sqrt((-4)^2-4(1)(-10)))/(2times1)$

$y=(4+-sqrt(16+40))/2$

$y=(4+-sqrt56)/2$

$y=(4+-2sqrt14)/2$

$y=2+-sqrt14$

How do you solve the rational equation (y+2)/y = 1/(y-5)(y+2)/y = 1/(y-5)?