How do you solve the rational equation $(y+2)/y = 1 / (y-5)$ ?

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Answer 1 · 2016-07-10T05:23:32

$y= 2+-sqrt14$

Taking, $sqrt14~=3.742$ ,

$y=5.742, or, -1.742$

$(y+2)/y=1/(y-5).$

$:. (y+2)(y-5)=y.$

$:. y^2+(-5+2)y-10-y=0.$

$:. y^2-3y-y=10.$

$:. y^2-4y=10$ .

$:.y^2-4y+4=10+4$ ............[completing square]

$:. (y-2)^2=(sqrt14)^2$

$:. y-2=+-sqrt14$

$:. y= 2+-sqrt14$

Taking, $sqrt14~=3.742$ ,

$y=5.742, or, -1.742$

Enjoy Maths.!

How do you solve the rational equation (y+2)/y = 1 / (y-5)(y+2)/y = 1 / (y-5)?