How do you solve the system $14x+5y=31, 2x-3y=-29$ ?

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Answer 1 · 2018-06-12T17:49:28

$y=9,x=-1$

$(1) 14x+5y=31$
$(2) 2x-3y=-29$

Let's eliminate the y's the isolate the x and solve for x.
To do this, multiply (1) by 3, and (2) by 5.

$(1) 42x+15y=93$
$(2) 10x-15y=-145$

(1)+(2) to eliminate y.

This leaves us with:

$52x=-52$

therefore $x=-1$

Substitute this back into one of the original equation to get:

$-14+5y=31$
Solve for y,
$y=9$

How do you solve the system 14x+5y=31, 2x-3y=-2914x+5y=31, 2x-3y=-29?