Question

How do you solve the system `2x +4y = 8` and `-5x +3y = 5`?

Answer 1

Given:
`{2x+4y=8`
`{-5x+3y=5`
Multiply the first by 5 and the second by 2:
`{10x+20y=40`
`{-10x+6y=10` now add them:
`0+26y=50`
So: `y=50/26=25/13`
Back in the first equation:
`2x+4(25/13)=8`
`2x=4/13`
`x=2/13`