How do you solve the system $-3x -8y = -9$ and $x+ 16y =3$ ?

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Answer 1 · 2015-06-20T17:28:44

The solution is: ${(x=3),(y=0):}$

First you multiply the first equation by 2 and get:

${(-6x-16y=-18),(x+16y=3):}$

Now you can add both equations to eliminate $y$ .

$-5x=-15$
$x=3$

Now if you substitute $x$ in the 2nd equation you can calculate that: $y=0$

How do you solve the system -3x -8y = -9-3x -8y = -9 and x+ 16y =3x+ 16y =3?