Question

How do you solve the system `3x + y = 11` and `–3x + 2y = 1`?

Answer 1

The easies way to reach a solution in this question is by summing two equations;

...............`cancel(3x) + y = 11`
...........`cancel (-3x) +2y =1`

............`3y = 12 => ul (y=4)`
`3x+ y= 11 => 3x + 4 = 11 => 3x= 7 => ul (x= 7/3)`