Question

How do you solve the system `4m+7n=0`, `-5m-3n=0`?

Answer 1

`m=0`, `n=0`

Explanation:

To solve the system of simultaneous equations `4m+7n=0` and `−5m−3n=0`, we multiply the two with different numbers so as to make coefficient of one variable equal in both.

Hence multiplying first by `5` and second by `4`, we get

`20m+35n=0` and `−20m−12n=0`.

Now as coefficient of `m` are same but have opposite sign, add them and we get

`23n=0` i.e. `n=0`.

Putting this in say first equation, we get

`4*0+7n=0` or `7n=0` or `n=0`