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How do you solve the system $4 x - 8 y = 0$ $4x - 8y = 0$ and $- 3 x + 8 y = - 7$ $-3x + 8y = -7$ ?

1 Answer

May 31, 2015

4x - 8y = 0 -> x = (8y)/4 = 2y

-3x + 8y = -7 -> -6y + 8y = -7 -> 2y = -7 -> y = -7/2

x = -7.

Check: -28 + 56/2 = 0 OK

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