How do you solve the system $5 x + 6 y = 4$ $5x + 6y = 4$ and $10 x + 12 y = 8$ $10x + 12y = 8$ ?

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How do you solve the system $5 x + 6 y = 4$ $5x + 6y = 4$ and $10 x + 12 y = 8$ $10x + 12y = 8$ ?

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Answer 1 · 2015-06-15T14:54:33

This system have $\infty$ $oo$ solutions because you have the equations of two coincident lines!

Explanation:

The second equation is equal to the first multiplied by $2$ $2$ ! So basically they are the same two lines one on top of the other.
Your two lines share an $\infty$ $oo$ number of common points and so they also share an $\infty$ $oo$ number of solutions!

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How do you solve the system $5 x + 6 y = 4$ $5x + 6y = 4$ and $10 x + 12 y = 8$ $10x + 12y = 8$ ?

1 Answer

Explanation:

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How do you solve the system 5x + 6y = 45x+6y=45x + 6y = 4 and 10x + 12y = 810x+12y=810x + 12y = 8?

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How do you solve the system $5 x + 6 y = 4$ $5x + 6y = 4$ and $10 x + 12 y = 8$ $10x + 12y = 8$ ?