How do you solve the system $- 6 x + 5 y = 1$ $-6x+5y=1$ and $6 x + 4 y = - 10$ $6x+4y=-10$ ?

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Answer 1 · 2015-06-10T09:41:13

The solution for the system of equations is
$x = - 1, y = - 1$ $color(red)( x =-1 , y=-1$

$- 6 x + 5 y = 1$ $-color(red)(6x)+5y=1$ ........equation $(1)$ $(1)$
$6 x + 4 y = - 10$ $color(red)(6x)+4y=-10$ .......equation $(2)$ $(2)$

Adding equations $1$ $1$ and $2$ $2$ to eliminate $6 x$ $6x$ :
$cancel6x+5y=1$
$cancel6x+4y=-10$

$9y = -9$
$color(red)(y=-1$

Substituting $y$ in equation $1$ to find $x$

$-6x = 1-5y$
$x = (1-5y)/-6$

$x = (1-5.(-1))/-6$

$x = (1+5)/-6$
$color(red)(x = -1$

How do you solve the system -6x+5y=1−6x+5y=1-6x+5y=1 and 6x+4y=-106x+4y=−106x+4y=-10?