How do you solve the system 8x+2y=2 and -4x=y+8?

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How do you solve the system 8x+2y=2 and -4x=y+8?

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Answer 1 · 2018-08-01T07:51:46

$no solution$ $"no solution"$

Explanation:

$8 x + 2 y = 2 \to (1)$ $8x+2y=2to(1)$

$- 4 x = y + 8 \to (2)$ $-4x=y+8to(2)$

$from (2) x y = - 4 x - 8$ $"from "(2)color(white)(x)y=-4x-8$

$substitute y = - 4 x - 8 into equation (1)$ $"substitute "y=-4x-8" into equation "(1)$

$8 x + 2 (- 4 x - 8) = 2$ $8x+2(-4x-8)=2$

$8 x - 8 x - 16 = 2$ $8x-8x-16=2$

$- 16 = 2 \leftarrow not possible$ $-16=2larr"not possible"$

$There is no solution to this system$ $"There is no solution to this system"$

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How do you solve the system 8x+2y=2 and -4x=y+8?

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