How do you solve the system of equations #2x+y=2# and #x-3y=-27#?

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Answer 1 · 2018-04-04T10:39:51

Solution: #x= -3, y=8#

#2x+y=2; (1), x-3y=-27 ; (2) #. Multiplying equation (2) by

#2# we get # 2x-6y=-54 ; (3),subtracting equation (3)

from equation (1) we get, # 7y=56 :. y=56/7=8 # . Putting

#y=8# in equation (1) we get, #2x+8=2 :. 2x= 2-8# or

#2x= -6 :. x = -3#

Solution: #x=-3, y=8# [Ans]