How do you solve the system of equations: 3x+2y-5=0, x=y+10?

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Answer 1 · 2015-08-14T12:18:35

The solutions are
$color(blue)(x=5,y=-5$

$3x+2y=5$ ................equation $1$
$x=color(blue)(y+10$ ..................equation $2$

Solving by substitution:

Substituting equation $2$ in equation $1$

$3x+2y=5$

$3*(color(blue)(y+10))+2y=5$

$3y+30+2y=5$

$5y=5-30$

$5y=-25$

$color(blue)(y=-5$

Finding $x$ by substituting $y$ in equation $2$
$x=y+10$
$x=-5+10$
$color(blue)(x=5$