How do you solve the system of equations: 3x - 4y = -30, 3x+2y=6?

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How do you solve the system of equations: 3x - 4y = -30, 3x+2y=6?

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Answer 1 · 2015-08-14T12:14:36

The solutions for the equations are
$x = - 2, y = 6$ $color(blue)(x=-2,y=6$

Explanation:

$3 x - 4 y = - 30$ $color(blue)(3x) - 4y = -30$ .....equation $1$ $1$
$3 x + 2 y = 6$ $color(blue)( 3x)+2y=6$ .............equation $2$ $2$

Solving by elimination.

Subtracting equation $2$ $2$ from $1$ $1$ results in elimination of $3 x$ $color(blue)(3x$
$cancel(color(blue)(3x)) - 4y = -30$
$-cancel(color(blue)( 3x))-2y=-6$

$-6y=-36$
$color(blue)(y=6$

Now we find $x$ by substituting $y$ in equation $1$
$3x - 4y = -30$
$3x = -30+4y$
$3x = -30+4*6$
$3x = -30+24$
$3x=-6$
$color(blue)(x=-2$

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How do you solve the system of equations: 3x - 4y = -30, 3x+2y=6?

1 Answer

Explanation:

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