How do you solve the system of equations: 5x + y = 1, 3x + 2y = 2?

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Answer 1 · 2015-08-15T12:48:05

The solutions are:
$color(blue)(x=0,y=1$

$5x + y = 1$ , multiplying this equation by $2$
$10x +color(blue)(2 y) = 2$ ........equation $1$

$3x +color(blue)( 2y) = 2$ ..........equation $2$

Solving by elimination

Subtracting equation $2$ from $1$ results in elimination of $color(blue)(2y$

$10x +cancelcolor(blue)(2 y) = 2$
$-3x -cancelcolor(blue)( 2y) = -2$

$7x=0$
$color(blue)(x=0$

Finding $y$ from equation $1$
$5x+ y = 1$
$y = 1-5x$
$y = 1-5 *0$
$color(blue)(y=1$