How do you solve the system of equations $y + 2 x = 3$ $y+2x=3$ and $- y + 4 = - x$ $-y+4=-x$ ?

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How do you solve the system of equations $y + 2 x = 3$ $y+2x=3$ and $- y + 4 = - x$ $-y+4=-x$ ?

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Answer 1 · 2016-12-02T02:22:46

$x = - \frac{1}{3}$ $x=-1/3$ and $y = \frac{11}{3}$ $y=11/3$ or $3 \frac{2}{3}$ $3 2/3$

Explanation:

$y + 2 x = 3$ $y+2x=3$
$- y + 4 = - x$ $-y+4=-x$

In the first equation, we can determine a value for $y$ $y$ .

$y + 2 x = 3$ $y+2x=3$

Subtract $2 x$ $2x$ from both sides.

$y = 3 - 2 x$ $y=3-2x$

In the second equation, substitute $y$ $y$ with $(3 - 2 x)$ $color(red)((3-2x))$ .

$- (3 - 2 x) + 4 = - x$ $-color(red)((3-2x))+4=-x$

Open the brackets and simplify. The product of two negatives is a positive, and that of a negative and positive is a negative.

$- 3 + 2 x + 4 = - x$ $-3+2x+4=-x$

$2 x + 1 = - x$ $2x+1=-x$

Add $x$ $x$ to both sides.

$3 x + 1 = 0$ $3x+1=0$

Subtract $1$ $1$ from both sides.

$3 x = - 1$ $3x=-1$

Divide both sides by $3$ $3$ .

$x = - \frac{1}{3}$ $x=-1/3$

In the first equation, substitute $x$ $x$ with $- \frac{1}{3}$ $-1/3$ .

$y + 2 x = 3$ $y+2x=3$

$y + 2 (- \frac{1}{3}) = 3$ $y+2(-1/3)=3$

Open the brackets and simplify.

$y - \frac{2}{3} = 3$ $y-2/3=3$

Add $\frac{2}{3}$ $2/3$ to both sides.

$y = 3 + \frac{2}{3}$ $y=3+2/3$

$y = 3 \frac{2}{3}$ $y=3 2/3$ or $y = \frac{11}{3}$ $y=11/3$

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How do you solve the system of equations $y + 2 x = 3$ $y+2x=3$ and $- y + 4 = - x$ $-y+4=-x$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you solve the system of equations y+2x=3y+2x=3 and −y+4=−x-y+4=-x?

1 Answer

Explanation:

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Impact of this question

How do you solve the system of equations $y + 2 x = 3$ $y+2x=3$ and $- y + 4 = - x$ $-y+4=-x$ ?