Step 1) Because the first equation is already solved for yy we can substitute -2x + 6−2x+6 for yy in the second equation and solve for xx:
2y + x = -52y+x=−5 becomes:
2(-2x + 6) + x = -52(−2x+6)+x=−5
(2 xx -2x) + (2 xx 6) + x = -5(2×−2x)+(2×6)+x=−5
-4x + 12 + x = -5−4x+12+x=−5
-4x + x + 12 = -5−4x+x+12=−5
-3x + 12 = -5−3x+12=−5
-3x + 12 - color(red)(12) = -5 - color(red)(12)−3x+12−12=−5−12
-3x + 0 = -17−3x+0=−17
-3x = -17−3x=−17
(-3x)/color(red)(-3) = (-17)/color(red)(-3)−3x−3=−17−3
(color(red)(cancel(color(black)(-3)))x)/cancel(color(red)(-3)) = 17/3
x = 17/3
Step 2) Subsitute 17/3 for x in the first equation and calculate y:
y = -2x + 6 becomes:
y = -34/3 + (3/3 xx 6)
y = -34/3 + 18/3
y = -16/3
The solution is: x = 17/3 and y = -16/3 or (17/3, -16/3)
