How do you solve the system of equations $y=-3x-1$ and $3x+y=-1$ ?

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Answer 1 · 2015-09-23T11:26:35

There are innumerable number of solutions.

$y=-3x-1$ -----------------------(1)
$3x+y=-1$ ------------------------(2)

Both the equations are one and the same.
Solve equation (2) for $y$

$y=-3x-1$ -------------------(2)

The second line will coincide with the first one.
Hence, there are innumerable number of solutions.

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