How do you solve the system of linear equations $y = 2 x + 3$ $y=2x+3$ , $- 2 x + y = 1$ $-2x+y=1$ ?

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How do you solve the system of linear equations $y = 2 x + 3$ $y=2x+3$ , $- 2 x + y = 1$ $-2x+y=1$ ?

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Answer 1 · 2017-09-17T18:08:18

$no solution$ $"no solution"$

Explanation:

$if we consider the 2 equations in slope-intercept form$ $"if we consider the 2 equations in "color(blue)"slope-intercept form"$

$∙ x y = m x + b$ $•color(white)(x)y=mx+b$

$where m is the slope and b the y-intercept$ $"where m is the slope and b the y-intercept"$

$- 2 x + y = 1 \to y = 2 x + 1 \Rightarrow m = 2$ $-2x+y=1toy=2x+1rArrm=2$

$y = 2 x + 3 \Rightarrow m = 2$ $y=2x+3rArrm=2$

$the 2 lines have the same slope and are therefore$ $"the 2 lines have the same slope and are therefore "$
$parallel$ $color(blue)"parallel"$

$hence no point of intersection thus no solution$ $"hence no point of intersection thus no solution"$
graph{(y-2x-3)(y-2x-1)=0 [-10, 10, -5, 5]}

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How do you solve the system of linear equations $y = 2 x + 3$ $y=2x+3$ , $- 2 x + y = 1$ $-2x+y=1$ ?

1 Answer

Explanation:

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How do you solve the system of linear equations y=2x+3y=2x+3, −2x+y=1-2x+y=1?

1 Answer

Explanation:

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How do you solve the system of linear equations $y = 2 x + 3$ $y=2x+3$ , $- 2 x + y = 1$ $-2x+y=1$ ?