How do you solve the system x−2y=8 and −x+3y=−5?

1 Answer
Bill K.
Jun 8, 2015

It can be solved either by substitution or by elimination.

1) Substitution: x−2y=8⇒x=2y+8⇒−(2y+8)+3y=−5

⇒y=3⇒x=6+8=14 and the unique answer is the point (x,y)=(14,3).

2) Elimination: add the two equations to get y=3 and then substitute into, for example, the second equation to get x=3y+5=9+5=14 so that the unique answer is the point (x,y)=(14,3).

Related questions
See all questions in Linear Systems with Multiplication
Impact of this question
2975 views around the world
You can reuse this answer
Creative Commons License