How do you solve the system $x-2y=8$ and $-x+5y=-5$ ?

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Answer 1 · 2015-06-10T17:50:26

The solution for the system of equations is:
$color(red)( x = 10 , y=1$

$color(red)(x)-2y=8$ .....equation $(1)$
$color(red)(-x)+5y=-5$ .....equation $(2)$

Adding equations $1$ and $2$ to eliminate $color(red)(x$
$cancelcolor(red)(x)-2y=8$
$cancelcolor(red)(-x)+5y=-5$

$3y = 3$
$color(red)(y=1$

Substituting $y$ in equation $1$ to find $x$

$x = 8+2y$
$x = 8+2xx1$
$color(red)( x = 10$

How do you solve the system x-2y=8 x-2y=8 and -x+5y=-5-x+5y=-5?