How do you solve using the quadratic formula $2x^2 – 4x + 7 = 0$ ?

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Answer 1 · 2015-05-02T04:06:44

D = d^2 = b^3 - 4ac = 16 - 56 = -40 -> $d = 2i.(sqr10)$

Since D < 0, there are no real roots. There are 2 complex roots:

$x1 = -b/(2a) + d/(2a) = 1 + (sqr10.i)/2$

$x2 = 1 - (sqr10.i)/2$

How do you solve using the quadratic formula 2x^2 – 4x + 7 = 02x^2 – 4x + 7 = 0?