How do you solve using the quadratic formula for $y = \frac{1}{2} {(x - 4)}^{2} + 18$ $y = 1/2 (x-4)^2 +18$ ?

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How do you solve using the quadratic formula for $y = \frac{1}{2} {(x - 4)}^{2} + 18$ $y = 1/2 (x-4)^2 +18$ ?

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Answer 1 · 2015-05-16T17:22:39

This equation, in vertex form, doesn't have x-intercepts. So you can't use the quadratic formula to solve y = 0.
Coordinates of vertex (4, 18). Parabola opens upward.

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How do you solve using the quadratic formula for $y = \frac{1}{2} {(x - 4)}^{2} + 18$ $y = 1/2 (x-4)^2 +18$ ?

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How do you solve using the quadratic formula for $y = \frac{1}{2} {(x - 4)}^{2} + 18$ $y = 1/2 (x-4)^2 +18$ ?