How do you solve $(x-1) /3 - (x-1) /2 = 6$ ?

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Answer 1 · 2016-04-02T08:47:18

$x=-35$

$color(blue)((x-1)/(3)-(x-1)/2=6$

First do fractional part. For that find the LCM of $3$ and $6$ which is $6$

So,

$rarr(2(x-1))/(2(3))-(3(x-1))/(3(2))=6$

$rarr(2(x-1))/(6)-(3(x-1))/(6)=6$

Use distributive property $color(brown)(a(b+c)=ab+ac$

$rarr(2x-2)/6-(3x-3)/6=6$

$rarr((2x-2)-(3x-3))/6=6$

Remember to change the signs

$rarr(2x-2-3x+3)/6=6$

Collect like terms

$rarr(-x+1)/6=6$

$rarr-x+1=6*6$

$rarr-x+1=36$

$rarr-x=36-1$

$rarr-x=35$

$color(green)(rArrx=-35$

How do you solve (x-1) /3 - (x-1) /2 = 6(x-1) /3 - (x-1) /2 = 6?